LINQ: Finding out duplicates in the list with multiple fields

I needed very quick simple “one line” solution to filter out duplicates in my list. So I have a List<T> where T is complex object with multiple properties. I wanted to filter out non unique items based on two fields. In database analogy my list is table with two columns based composite primary key and I need to select non-distinct values.

Here is sample code:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace LinqDuplicates
{
    public class Item
    {
        public int ID { get; set; }
        public string Name { get; set; }
    }

    class Program
    {
        static void Main(string[] args)
        {
            List items = new List();
            items.Add(new Item { ID = 0, Name = "John" });
            items.Add(new Item { ID = 1, Name = "Thorsten" });
            items.Add(new Item { ID = 1, Name = "Thorsten" });
            items.Add(new Item { ID = 2, Name = "Rapunzel" });
            items.Add(new Item { ID = 3, Name = "Rapunzel" });
            items.Add(new Item { ID = 3, Name = "Grinch" });

            var duplicates = items.GroupBy(x => new {x.ID, x.Name})
                            .Where(g => g.Count() > 1)
                            .Select(g => g.Key);

            foreach (var val in duplicates)
            {
                Console.WriteLine(val.ID + " " + val.Name);
                Console.ReadLine();
            }

        }
    }
}

So this code will select just one duplicate I have in list and that is Item with ID=1 and Name=”Thorsten”.

Another way around to get all distinct values would be:

var distinct = items.Select(item => new { item.ID, item.Name }).Distinct();

This results in list with all the distinct values based on two fields (composite key) criteria.

linq-distinct

About me

Bizic Bojan is Freelance Software Development Consultant with focus on C++, Qt and .NET based software solutions development. 

 

Disclaimer:

The opinions expressed herein are my own personal opinions and do not represent my employer’s view in any way.

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